x^2-25/3x^2+20x+25

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Solution for x^2-25/3x^2+20x+25 equation:


x in (-oo:+oo)

x^2-((25/3)*x^2)+20*x+25 = 0

x^2+(-25/3)*x^2+20*x+25 = 0

20*x-22/3*x^2+25 = 0

DELTA = 20^2-(-22/3*4*25)

DELTA = 3400/3

DELTA > 0

x = ((3400/3)^(1/2)-20)/(-22/3*2) or x = (-(3400/3)^(1/2)-20)/(-22/3*2)

x = -3/44*((3400/3)^(1/2)-20) or x = 3/44*((3400/3)^(1/2)+20)

x in { -3/44*((3400/3)^(1/2)-20), 3/44*((3400/3)^(1/2)+20) }

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